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September 5, 2003, 2:43 pm
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I am compiled openssh3.6.1p2 with PAM and using RSA Security (ACE) token.
the command I used to compile ssh as follow:
1. ./configure --with-pam
3. make install
After starting the sshd daemon, I authenticate using the command
On the SecurID server I was watching the log monitor and I saw the following
"ACCESS DENIED, syntax error" before I get the prompt for Passcode
and when I put my passcode, it let me login. Doing that for several time
SecurID puts me in the "next token code" and then disable my token.
I called RSA security and we found out that the problem was in the openssh.
when RSA sent me a compiled openssh that can be found on the internet, then
everything worked just fine with no errors.
The fact is that we can not depend on finding a compiled openssh with PAM on
internet, so I compiled my own version with Pam
but Of course I am sure I am missing some compilation switches and options.
SO my question to you is :
How do I compile an openssh that works with PAM on Unix or Linux.
Than you very much
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