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Posted by jh3an on March 10, 2008, 5:44 pm
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Here is mysterious code, please look:
$x = '12aba34ba5';
@num = split /(a|b)+/, $x;
now, @num has ('12','a','34','a','5').
I don't understand.
I was expecting that @num would have '12','34','5'.
However, it is not.
Why..? Please help me.
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Posted by Joost Diepenmaat on March 10, 2008, 5:48 pm
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> Here is mysterious code, please look:
>
> $x = '12aba34ba5';
> @num = split /(a|b)+/, $x;
>
> now, @num has ('12','a','34','a','5').
>
> I don't understand.
> I was expecting that @num would have '12','34','5'.
> However, it is not.
See perldoc -f split:
If the PATTERN contains parentheses, additional list elements
are created from each matching substring in the delimiter.
split(/([,-])/, "1-10,20", 3);
produces the list value
(1, '-', 10, ',', 20)
IOW, you can use some non-capturing syntax, like:
@num = split /[ab]+/,$x;
to discard the separators.
--
Joost Diepenmaat | blog: http://joost.zeekat.nl/ | work: http://zeekat.nl/
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Posted by xhoster on March 11, 2008, 12:54 pm
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> > Here is mysterious code, please look:
> >
> > $x = '12aba34ba5';
> > @num = split /(a|b)+/, $x;
> >
> > now, @num has ('12','a','34','a','5').
> >
> > I don't understand.
> > I was expecting that @num would have '12','34','5'.
> > However, it is not.
>
> See perldoc -f split:
>
> If the PATTERN contains parentheses, additional list elements
> are created from each matching substring in the delimiter.
That really should say "If the PATTERN contains capturing parentheses,..."
^^^^^^^^^
Xho
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The costs of publication of this article were defrayed in part by the
payment of page charges. This article must therefore be hereby marked
advertisement in accordance with 18 U.S.C. Section 1734 solely to indicate
this fact.
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Posted by Peter Makholm on March 10, 2008, 5:52 pm
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> Why..? Please help me.
Read 'perldoc -f split'.
[...]
If the PATTERN contains parentheses, additional list elements
are created from each matching substring in the delimiter.
split(/([,-])/, "1-10,20", 3);
produces the list value
(1, '-', 10, ',', 20)
[...]
//Makholm
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Posted by Riad KACED on March 10, 2008, 9:24 pm
Please log in for more thread options I would propose the following for your case :
@num = split /D+/,$x;
This will split with any a-zA-Z
Riad.
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