Do you have a question? Post it now! No Registration Necessary. Now with pictures!
- Posted on
- exec("ls *.*") gives unexpected output
October 6, 2005, 12:00 am
rate this thread
// current directory
echo getcwd() . "<br />";
print ( exec("ls *.*") );
should display the names of the four files (it does in an ssh session)
which are located in public_html, but instead it displays just one
filename, that of this script.
I don't understand why?
Re: exec("ls *.*") gives unexpected output
It would be a good idea to refer to the manual:
Note in particular:
The last line from the result of the command. If you need to execute a
command and have all the data from the command passed directly back
without any interference, use the passthru() function."
Chris Hope | www.electrictoolbox.com | www.linuxcdmall.com