exec("ls *.*") gives unexpected output

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The second line of this script
// current directory
echo getcwd() . "<br />";
print ( exec("ls *.*") );
should display the names of the four files (it does in an ssh session)
which are located in public_html, but instead it displays just one
filename, that of this script.

I don't understand why?

Re: exec("ls *.*") gives unexpected output

kurt.krueckeberg@gmail.com wrote:

Quoted text here. Click to load it

It would be a good idea to refer to the manual:

Note in particular:
"Return Values
The last line from the result of the command. If you need to execute a
command and have all the data from the command passed directly back
without any interference, use the passthru() function."

Chris Hope | www.electrictoolbox.com | www.linuxcdmall.com

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