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- regexp + floor
December 1, 2005, 6:48 am
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Re: regexp + floor
You could, however, do it in the replacement string part
of an s///e operator.
You must not have looked very hard.
You are expected to check the Perl FAQ *before* posting
to the Perl newsgroup:
perldoc -q round
Does Perl have a round() function? What about ceil() and floor()?
Tad McClellan SGML consulting
email@example.com Perl programming
Fort Worth, Texas