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Posted by sopan.shewale@gmail.com on January 31, 2008, 6:14 pm
Please log in for more thread options Hi,
People have already answered your question - i just thought of adding
value to the discussion.
Have a look at the articles:
[1]. http://blog.stevenlevithan.com/archives/regex-recursion [2]. http://perl.plover.com/yak/regex/samples/slide083.html
This articles will help you to understand the solutions posted in this
discussion and give high level understanding about the problem.
Regards,
--sopan shewale
> _
> Si (silicium_a...@rmony-p.ath.cx) wrote on VCCLXVI September MCMXCIII in
> :) Beeing new to perl and not wanting to learn using it like assembler, I
> :) need to delete parts of a single line (possibly long) that are enclosed
> :) between nested brackets:
> :)
> :) abcd efgh [ij: 123-[456]-klm; nop-789]; qrst; uvw [xyz: 98-76-[ef]; gh;
> :) ijkl] (mnop)
> :)
> :) The comments between [] must be discarded to split with ';' delimiter.
> :) The expected result is:
> :) array[0] == "abcd efgh"
> :) array[1] == "qrst"
> :) array[2] == "uvw (mnop)"
> :)
> :) Thanks for a magic formula.
>
> The magic formula is: \s*(\[[^][]*+(?:(?1)[^][]*+)*\])
>
> my $_ = "abcd efgh [ij: 123-[456]-klm; nop-789]; qrst; uvw " .
> "[xyz: 98-76-[ef]; gh;ijkl] (mnop)";
>
> s {}g;
>
> my @array = split /;\s*/;
>
> say qq {array[$_] == "}, $array [$_], qq for 0 .. $#array;
>
> __END__
> array[0] == "abcd efgh"
> array[1] == "qrst"
> array[2] == "uvw (mnop)"
>
> Abigail
> --
> perl -we 'print split /(?=(.*))/s => "Just another Perl Hacker\n";'
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