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Subject Author Date
code help jammer 02-27-2008
|--> Re: code help Jürgen Exner02-27-2008
---> Re: code help John W. Krahn02-27-2008
Posted by jammer on February 27, 2008, 9:54 pm
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 Why does this give a syntax error?


# not 2 arguments, print usage
if ($#ARGV != 1) {
print "\nusage: " . $ARGV[0] . "\[backupDir\] \
[backupConfigFile\]\n";
}


Posted by Jürgen Exner on February 27, 2008, 10:10 pm
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>Why does this give a syntax error?
>
>
># not 2 arguments, print usage
>if ($#ARGV != 1) {
> print "\nusage: " . $ARGV[0] . "\[backupDir\] \
>[backupConfigFile\]\n";
>}

It doesn't for me:

        C:\tmp>type t.pl
        # not 2 arguments, print usage
        if ($#ARGV != 1) {
         print "\nusage: " . $ARGV[0] . "\[backupDir\] \
        [backupConfigFile\]\n";
        }

        C:\tmp>perl -c t.pl
        t.pl syntax OK

jue

Posted by John W. Krahn on February 27, 2008, 10:31 pm
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jammer wrote:
> Why does this give a syntax error?

There is no syntax error there.

> # not 2 arguments, print usage
> if ($#ARGV != 1) {

That's a great way to confuse a newby. Why does the comment say "2
arguments" but you are comparing the variable to 1? Try it like this:

# not 2 arguments, print usage
if ( @ARGV != 2 ) {

> print "\nusage: " . $ARGV[0] . "\[backupDir\] \

Unlike C, Python, etc. the first argument of @ARGV is *not* the program
name, you want the $0 variable instead.

> [backupConfigFile\]\n";
> }


John
--
Perl isn't a toolbox, but a small machine shop where you
can special-order certain sorts of tools at low cost and
in short order. -- Larry Wall

Posted by jammer on February 27, 2008, 11:11 pm
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> jammer wrote:
> > Why does this give a syntax error?
>
> There is no syntax error there.
>
> > # not 2 arguments, print usage
> > if ($#ARGV !=3D 1) {
>
> That's a great way to confuse a newby. =A0Why does the comment say "2
> arguments" but you are comparing the variable to 1? =A0Try it like this:
>
> # not 2 arguments, print usage
> if ( @ARGV !=3D 2 ) {
>
> > =A0 =A0 =A0 =A0 print "\nusage: " . $ARGV[0] . "\[backupDir\] \
>
> Unlike C, Python, etc. the first argument of @ARGV is *not* the program
> name, you want the $0 variable instead.

I had a missing semi-colon and the error pointed to that block. :-(

Posted by Jim Gibson on February 28, 2008, 2:47 pm
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In article

> > jammer wrote:
> > > Why does this give a syntax error?
> >
> > There is no syntax error there.
> >
> > > # not 2 arguments, print usage
> > > if ($#ARGV != 1) {
> >
> > That's a great way to confuse a newby.  Why does the comment say "2
> > arguments" but you are comparing the variable to 1?  Try it like this:
> >
> > # not 2 arguments, print usage
> > if ( @ARGV != 2 ) {
> >
> > >         print "\nusage: " . $ARGV[0] . "\[backupDir\] \
> >
> > Unlike C, Python, etc. the first argument of @ARGV is *not* the program
> > name, you want the $0 variable instead.
>
> I had a missing semi-colon and the error pointed to that block. :-(

That is why it is always best to post a *complete* program, not just a
code fragment. Compilers are not always very good about diagnosing the
source of errors and identifying the exact line where the error is
located.

--
Jim Gibson

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