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Regexp to search over several lines in one string
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Subject Author Date
Regexp to search over several lines in one string d99alu 01-27-2008
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Posted by d99alu on January 27, 2008, 7:18 am
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 Hi!

I have a string, and I want to remove everything behind the ">"
character. The string contains new line characters that I don't want
to remove.

my $string = "line1
line2>
line3";

Why don't I get a match and replacement with this?

$string =~ s/^([^>]*>)/$1/;

I would expect the string to contain:

"line1
line2>"

But it still contains "line3"!!!

Why is this?
Any suggestions for how to do this in an other 8working) manner?

Best Regards,
Andreas - Sweden

Posted by Dr.Ruud on January 27, 2008, 7:39 am
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 d99alu@efd.lth.se schreef:

> I have a string, and I want to remove everything behind the ">"
> character. The string contains new line characters that I don't want
> to remove.

s/(?:<=>).*//s;

See perldoc perlre, search for "look-behind".

--
Affijn, Ruud

"Gewoon is een tijger."

Posted by John W. Krahn on January 27, 2008, 10:06 am
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Dr.Ruud wrote:
> d99alu@efd.lth.se schreef:
>
>> I have a string, and I want to remove everything behind the ">"
>> character. The string contains new line characters that I don't want
>> to remove.
>
> s/(?:<=>).*//s;

ITYM: s/(?<=>).*//s;


John
--
Perl isn't a toolbox, but a small machine shop where you
can special-order certain sorts of tools at low cost and
in short order. -- Larry Wall

Posted by Dr.Ruud on January 27, 2008, 10:59 am
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John W. Krahn schreef:
> Dr.Ruud:
>> d99alu:

>>> I have a string, and I want to remove everything behind the ">"
>>> character. The string contains new line characters that I don't want
>>> to remove.
>>
>> s/(?:<=>).*//s;
>
> ITYM: s/(?<=>).*//s;

Yes. (aaargh, oops again)

--
Affijn, Ruud

"Gewoon is een tijger."


Posted by Dr.Ruud on January 27, 2008, 11:11 am
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Dr.Ruud schreef:
> d99alu:

>> I have a string, and I want to remove everything behind the ">"
>> character. The string contains new line characters that I don't want
>> to remove.
>
> s/(?:<=>).*//s;
>
> See perldoc perlre, search for "look-behind".

I also forgot the newline. Maybe this does what you need:

s/(?<=>).*/\n/s;

(doesn't keep any of the original newlines; even adds one when none was
there)

--
Affijn, Ruud

"Gewoon is een tijger."


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