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Problem with loop control LAST exiting prematurely
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Subject Author Date
Problem with loop control LAST exiting prematurely Rodion 03-18-2008
Posted by Tad J McClellan on March 18, 2008, 9:45 pm
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> Jednom davno, ne znam vise kad, xhoster@gmail.com duboko zamisljen/a
> rece:

>> If you want to pursue the matter,
>> post a complete, runnable script to illustrate this.

> Well, I'm most certanly misundrestanding something, but I'd like to know
> what, so I don't make the same mistake twice :/


Then simply post a complete, runnable program to illustrate the
problem you are having.


> The following subrutine


A snippet of subroutine is not a complete program that we can run.


--
Tad McClellan
email: perl -le "print scalar reverse qq/moc.noitatibaher0cmdat/"

Posted by Brian Helterline on March 18, 2008, 3:42 pm
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 Rodion wrote:
> Jednom davno, ne znam vise kad, John W. Krahn duboko zamisljen/a rece:
>
>> Couldn't you just write that as:
>>
>> $found = 1 if exists $cb;
>
> Well, I have to thank you for putting me on the right track!
>
> There was a problem with some numeric data having prefixed zeroes while
> some of the hash keys did not so there could be no match ( 0567 != 567).

If you are doing the testing using numeric comparison, then they are equal.

print "equal" if '0567' == '567';

--
-brian

Posted by Lawrence Statton on March 18, 2008, 3:58 pm
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> If you are doing the testing using numeric comparison, then they are equal.
>
> print "equal" if '0567' == '567';
>
> --
> -brian

Does not print "equal"

However

perl -le 'print "equal" if '0567' == '375''

Does.

Why can't programmers tell Haloween from Christmas?

Because OCT 31 == DEC 25









--
        Lawrence Statton - lawrenabae@abaluon.abaom s/aba/c/g
Computer software consists of only two components: ones and
zeros, in roughly equal proportions. All that is required is to
place them into the correct order.

Posted by Brian Helterline on March 19, 2008, 7:29 pm
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Lawrence Statton wrote:
>> If you are doing the testing using numeric comparison, then they are equal.
>>
>> print "equal" if '0567' == '567';
>>
>> --
>> -brian
>
> Does not print "equal"

It does on my system:


C:\>perl -le "print 'equal' if '0567' == '567'"
equal

C:\>perl -v

This is perl, v5.8.8 built for MSWin32-x86-multi-thread
(with 33 registered patches, see perl -V for more detail)

Posted by Lawrence Statton on March 18, 2008, 3:58 pm
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> If you are doing the testing using numeric comparison, then they are equal.
>
> print "equal" if '0567' == '567';
>
> --
> -brian

Does not print "equal"

However

perl -le 'print "equal" if '0567' == '375''

Does.

Why can't programmers tell Haloween from Christmas?

Because OCT 31 == DEC 25

--
        Lawrence Statton - lawrenabae@abaluon.abaom s/aba/c/g
Computer software consists of only two components: ones and
zeros, in roughly equal proportions. All that is required is to
place them into the correct order.

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