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FAQ 4.46 How do I handle linked lists?

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FAQ 4.46 How do I handle linked lists? PerlFAQ Server 02-28-2008
Posted by PerlFAQ Server on February 28, 2008, 9:03 pm
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This is an excerpt from the latest version perlfaq4.pod, which
comes with the standard Perl distribution. These postings aim to
reduce the number of repeated questions as well as allow the community
to review and update the answers. The latest version of the complete
perlfaq is at http://faq.perl.org .

--------------------------------------------------------------------

4.46: How do I handle linked lists?

In general, you usually don't need a linked list in Perl, since with
regular arrays, you can push and pop or shift and unshift at either end,
or you can use splice to add and/or remove arbitrary number of elements
at arbitrary points. Both pop and shift are O(1) operations on Perl's
dynamic arrays. In the absence of shifts and pops, push in general needs
to reallocate on the order every log(N) times, and unshift will need to
copy pointers each time.

If you really, really wanted, you could use structures as described in
perldsc or perltoot and do just what the algorithm book tells you to do.
For example, imagine a list node like this:

$node = {
VALUE => 42,
LINK => undef,
};

You could walk the list this way:

print "List: ";
for ($node = $head; $node; $node = $node->) {
print $node->, " ";
}
print "\n";

You could add to the list this way:

my ($head, $tail);
$tail = append($head, 1); # grow a new head
for $value ( 2 .. 10 ) {
$tail = append($tail, $value);
}

sub append {
my($list, $value) = @_;
my $node = { VALUE => $value };
if ($list) {
$node-> = $list->;
$list-> = $node;
}
else {
$_[0] = $node; # replace caller's version
}
return $node;
}

But again, Perl's built-in are virtually always good enough.



--------------------------------------------------------------------

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