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Distance Lat Long Caculations bigtone 08-03-2006
Posted by bigtone on August 3, 2006, 7:44 pm
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 Is there a way of computing the new lat2 and long2 of a position
reached after travelling x metres on a bearing of y degrees given a
known start position of say lat1 long1. It is like the inverse of the
Haversine formulaes but i am not clever enough to do the inversion.
Mant thank for any help
Tony


Posted by Paul Cooper on August 4, 2006, 4:57 am
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>Is there a way of computing the new lat2 and long2 of a position
>reached after travelling x metres on a bearing of y degrees given a
>known start position of say lat1 long1. It is like the inverse of the
>Haversine formulaes but i am not clever enough to do the inversion.
>Mant thank for any help
>Tony


Yes - use the "geod" program bundled with proj4
(http://www.remotesensing.org/proj/). Because of small angle problems,
geodetic distance calculations using trigonometric formulae directly
are error-prone. However, the formula would be:

1) Express the distance in angular units (i.e. divide by 2*Pi*Radius
of the Earth to get it in radians).
2) Cos(new co-Latitude) = -cos(co-Latitude)*cos(distance) +
sin(co-Latitude)*sin(distance)*cos(Azimuth)
3) Sin (difference in longitude) = sin(distance)*sin(Azimuth)/sin(new
CoLatitude)

All these are derived from the standard sine and cosine rules of
trigonometry; I may have made some mistakes as I did the derivation in
my head.

Paul Cooper

Posted by Seymour Dupa on December 29, 2006, 11:59 pm
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http://www.meridianworlddata.com/Distance-Calculation.asp
http://www.movable-type.co.uk/scripts/LatLong.html
http://mathforum.org/library/drmath/view/51816.html


> Is there a way of computing the new lat2 and long2 of a position
> reached after travelling x metres on a bearing of y degrees given a
> known start position of say lat1 long1. It is like the inverse of the
> Haversine formulaes but i am not clever enough to do the inversion.
> Mant thank for any help
> Tony
>



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